Same trick will work next year too!
2^1
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Having kids at 19
Bruh
And pregnant at 18
This guy maths
18 3/12 ~ 19 3/12
Don’t worry it works for all factors of ten. Like 10 = 1
Took me too long to realize the 0 can be an exponent.
Damn, that took me waaay too long to get…
Not my brightest moment… 😅
But when you finally get it
My kids are √-1
Kind of hard to define but refer to themselves as I?
I know I’m bad at math but I don’t understand how 2x0=0 but 2^0=1
How are they different answers when they’re both essentially multiplying 2 by zero?
Someone with a bigger brain please explain this
Edit: I greatly appreciate all the explanations but all they’ve done is solidify the fact that I’ll never be good at math 😭
subtracting one from Exponent means halving (when the base is two):
2⁴ = 16 2³ = 8 2² = 4 2¹ = 2 2⁰ = 1
It’s a simple continuation of the pattern and required for mathemarical rules to work.
This isn’t strictly speaking a proof, but it did help me to accept it as it demonstrates the function that makes it 1.
2^3 = 2x2x2
2^2 = 2x2
(23)/(22) = (2x2x2)/(2x2) = 2
= 2^(3-2)
In general terms:
(xa)/(xb) = x^(a-b)
If a and b are the same number this is x^0 and obviously (xa)/(xa) is one because anything divided by itself is 1.
Hope that helps
Yes, of course, obviously…JFC, what??
2^(a-b) = (2a)/(2b)
You can see this in the example above but perhaps it’s better to use different powers to make things a bit clearer.
2^5=2x2x2x2x2
2^3=2x2x2
(25)/(23)=(2x2x2x2x2)/(2x2x2)
You can cancel 3 of the 2s from the top and bottom of the fraction to be left with 2x2, or 2^2.
I.e. (25)/(23)=2^2
The quicker way to calculate this is doing 2^(5-3) which when you resolve the bracket is obviously just 2^2 or 2x2.
If both numbers in the bracket are the same the bracket will always resolve to 0, which is the same as saying a number divided by itself, any number divided by itself is one so it follows that any number to the power 0 is also 1 (because it’s essentially exactly the same calculation).
It’s just 1+1-1 with more steps, I don’t see the problem.
You can think of 1 as the “empty product” (or the “neutral element of multiplication” if you want to be fancy). 2^x means you have x factors of 2. If you have 0 factors, you have the “empty product”
In addition to the explanation others have mentioned, here it is in graph form. See the where the graph of 2^x intersects the y axis (when x=0):
https://people.richland.edu/james/lecture/m116/logs/exponential.html
This also has some additional verbal explanations:
http://scienceline.ucsb.edu/getkey.php?key=2626
The simplest way I think of it is by the properties of exponentials:
2^3 / 2^2 = (2 * 2 * 2) / (2 * 2) = 2 = 2^(3-2)
Dividing two exponentials with the same base (in this case 2) is the same as that same base (2) to the power of the difference between the exponent in the numerator minus the exponent in the denominator (3 and 2 in this case).
Now lets make both exponents the same:
2^3 / 2^3 = 8/8 = 1
2^3 / 2^3 = 2^(3-3) = 2^0 = 1
I see other people have posted good explanations, but I think the simplest explanation has to do with how you break down numbers. Lets take a number, say, 124. We can rewrite it as 100 + 20 + 4 and we can rewrite that as 1 * 10^2 + 2 * 10^1 + 4 * 10^0 and I think you can see why anything raised to the 0th power has to equal 1. Numbers and math wouldn’t work if it didn’t.
Its not the same. And theres proof, why.
0 is the neutral element for addition. This is why when we have a number then 0 + number = number (0 doesnt change the value in addition) and why 0 x number = 0 (if you add a number 0 times you will have 0). (Multiplication is adding one of the numbers to itself the number of times designated by the second number)
The same way 1 is the neutral element for multiplication. This is why when you have some number then 1 * number = number. This is also why number^0 = 1 (if you never multiply by a number you are left with the neutral element. It would be weird if powering by 0 left you with 0 for example because of how negative powers work)
This is the level 1 answer.
The level 0 answer is that it is this way because all of mathematics is a construct designed to ease problem solving and all people collectively agreed that doing it this way is way more useful (because it is)
Choose which one you want
This dude is great at explaining math, including this: https://yewtu.be/watch?v=r0_mi8ngNnM
2^0 isn’t multiplying by zero. Considering this law: 2^a / 2^b = 2^(a-b)
it’s obvious why 2^0 = 1
If a=b you’re dividing by the same number resulting in 1.Unfortunately, I cannot explain/prove the first law though.
The first rule is just simple division:
(2222) / (22) =
(2/2) * (2/2) * 2 * 2=
1 * 1 * 2 * 2 =
2 * 2 =
4
Writing in terms of powers:
(2^4) / (2^2) =
(2^(4-2)) =
(2^2) =
4
The two bottom 2’s “cancel out” (really they just divide into one another to make 1’s) two of the top 2’s and you’re left with two top twos.
Well looks like some people already answered your question but let me show you quick proof video that may help you understand how powers work: https://youtu.be/kPTp82EGjv8?feature=shared
Here is an alternative Piped link(s):
https://piped.video/kPTp82EGjv8?feature=shared
Piped is a privacy-respecting open-source alternative frontend to YouTube.
I’m open-source; check me out at GitHub.
I hate that I get this
I genuinely feel bad for you, understanding 4th grade math must be such a burden, thank you for carrying this weight.
I don’t get it.
2⁰=1
I still don’t get it.
The 2⁰ looks like 20 (for the 20yr old’s birthday) but when you calculate 2 to the power of 0 it’s equal to 1 (which is for the baby’s birthday). It’s a math joke, hope that helps
Oh, I get it! I get jokes!
2^0 =1^1
That’s not a meme.
c/gatekeeping
“Look at this zebra”
“That’s a giraffe”
“Stop gatekeeping”
It’s not less of a meme than most of the other posts in this community.
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Good luck trying that in two years.
Ah yes. How fitting for a young new person in the world. A reminder that 2°C of warming above the pre-industrial mean would be catastrophic, but also is a good lower-limit of what to expect based on current intentions.
Where are my programmer buddies? 🤘
dying inside from learning c++
tbh not as bad as i expected but still
It’s been a while, but I think I remember this one. Lim 1/n =0 as n approaches infinity. Let x^0 be undefined. For any e>0 there exists an n such that |x^(1/n) -1| < e. If you desire x^(1/n) to be continuous at 0, you define x^0 as 1.
E2a: since x^(1/n)>1, you can drop the abs bars. I think you can get an inequality to pick n using logs.
Simpler: x^1 = x, x^-1 = 1/x
x^1 * x^-1 = x^0 = x/x = 1.
Of course, your explanation is the “correct” one - why it’s possible that x^0=1. Mine is the simple version that shows how logic checks out using algebraic rules.
Of course you both assume x =/= 0 though.
